apoc.coll.removeAll

Function

apoc.coll.removeAll(first, second) - returns first list with all elements of second list removed

Signature

apoc.coll.removeAll(first :: LIST? OF ANY?, second :: LIST? OF ANY?) :: (LIST? OF ANY?)

Name	Type	Default
first	LIST? OF ANY?	null
second	LIST? OF ANY?	null

Name

Type

Default

first

LIST? OF ANY?

null

second

LIST? OF ANY?

null